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Q.

If [λ22λ+1λ21λ2+3λ1λ2]=Aλ2+Bλ+C  where A, B, C are matrices then B + C =

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a

[1141]

b

[1141]

c

[1141]

d

[1141]

answer is A.

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Detailed Solution

put λ=1, we get A+B+C=0-130 , --------(1)  put  λ=-1 we get A-B+C=4-3-30----------(2)

put λ=0 we get C= 1-211

Eq (1)-(2)

2B=-4260     B=-2130

B+C=-1-141

 

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