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If $250 c m^{3}$ of an aqueous solution containing 0.73g of a protein A is isotonic with one litre of another aqueous solution containing 1.65g of a protein B, at 298K, the ratio of the molecular masses of A and B is ______ $\times 10^{- 2}$ (to the nearest integer).

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answer is 177.

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Detailed Solution

$[0.73 / M_{A}] \times [1000 / 250] = 1.65 / M_{B} [M_{A} / M_{B}] = [73 \times 4] / 165 = 1.769 = 1.769 \times 10^{- 2} = 177 \times 10^{- 2}$

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