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If 27⁹⁹⁹ is divided by 7 than remainder is

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answer is B.

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Detailed Solution

$27^{999} = {(28 - 1)}^{999} = 28^{n} - C_{1} 28^{n - 1} + - - - + C_{n - 1} 28 - 1$
where n =999
$= 28 m - 1 = 7 (4 m) - 1 = 7 [4 m - 1] + 6$
Remainder is : 6

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