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Q.

If $2^{a} + 3^{b} = 17$ and $2^{a + b} - 3^{b + 1} = 5$ , then $(a, b) =$

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a

(3, 2)

b

(2, 1)

c

(1, 2)

d

(2, 3)

answer is B.

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Detailed Solution

2^{a} + 3^{b} = 17

$2^{a + b} - 3^{b + 1} = 5$

If $a = 3, b = 2$

$2^{3} + 3^{2} = 17$

$8 + 9 = 17$

$2^{3 + 2} - 3^{2 + 1}$

$32 - 27 = 5$

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