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Q.

If (2k–5)x2–4x–15=0 and (3K–8) x2–5x–21 = 0 have a common root then K =

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a

2

b

1

c

6

d

4

answer is C.

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Detailed Solution

(c1a2 - c2a1)2 = (a1b2 - a2b1)(b1c2 - b2c1)

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If (2k–5)x2–4x–15=0 and (3K–8) x2–5x–21 = 0 have a common root then K =