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Q.

If 2x3+3x2+ax+b  is divided by (x2)  leaves the remainder 2  and divided by (x+2)  leaves the remainder 2 , then the values of a,b  are respectively

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a

7,12

b

7,12

c

7,12

d

7,12

answer is D.

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Detailed Solution

f(x)=2x3+3x2+ax+b

f(2)=2

16+12+2a+b=2

2a+b=26(1)

f(2)=2

16+122a+b=2

2a+b=2(2)

From (1)&(2)

a=7  , b=12

7,12

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