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If $2 x + k y - 10 = 0, 5 x + 2 y - 7 = 0$ are parallel, then the value of $‘ k ’$ is

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\frac{4}{3}

\frac{4}{5}

\frac{5}{3}

$\frac{3}{6}$

answer is B.

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Detailed Solution

$2 x + k y - 10 = 0, 5 x + 2 y - 7 = 0$

$a x + b y + c = 0, a x + b y + c = 0$

slope $(m_{1}) = \frac{- 2}{k}$ , slope $(m_{2}) = \frac{- 5}{2}$

Given lines are parallel

$m_{1} = m_{2}$

$\frac{- 2}{k} = \frac{- 5}{2}$

$k = \frac{4}{5}$

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