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Q.

If (3, -4) and (-6, 5) are the extremities of the diagonal of a parallelogram and (-2, 1) is its third vertex, then its fourth vertex is:

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a

(-1, 0)

b

(0, -1)

c

None of these 

d

(-1 , 1)

answer is A.

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Detailed Solution

Given that, (3, -4) and (-6, 5) are the extremities of the diagonal and (-2, 1) is its third vertex.
We need to find the 4th vertex.
Let A(3, -4) and C(-6, 2) be the extremities of diagonal AC and B(-1,-3), D(x,y) the extremities of diagonal BD.
Midpoint of two point (x1,y1) & (x2,y2) is , (x1+x22,y1+y22).
Since the diagonals of a parallelogram bisect each other.
Therefore,
Coordinates of midpoint of AC = Coordinates of midpoint of BD.
(3+(-6)2,(-4)+22)=((-1)+x2,(-3)+y2)
Equating x coordinates,
3-62=x-12 -32=x-12 x=-2 And, equating y coordinates,
-4+22=y-32 -22=y-32 y=1 Thus, the coordinates of the fourth point is (-2,1).
Therefore, option (1) is correct.
 
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