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If 3 litre of $1 M {Ag}_{2} {SO}_{4}$ is mixed with 4 litre of $1 M$ $NaCI$ solution, then what will be the sum of molarity of all the ions?

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1 M

7 M

2.42 M

1.28 M

answer is D.

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Detailed Solution

${Ag}_{2} {SO}_{4} + 2 NaCl ⟶ 2 AgCl + {Na}_{2} {SO}_{4}$

$3 mole 4 mole x 2 mole$

$\begin{array}{rcccc} Ag & + & {SO}_{4}^{2} & {Na}^{+} & {SO}_{4}^{2 -} \\ 2 & 1 & 4 & 2 \end{array}$

$[Conc.] = \frac{9}{7} = 1.28$

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