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If 30 g sample of a chloroplatinate salt of diacidic organic Lewis base on ignition produces 5 g of white residue, then what will be the molar mass of the base? $[Pt = 195]$

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1170

760

410

380

answer is A.

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Detailed Solution

$\underset{30 g}{B_{2}} {(H_{2} {PtCl}_{6})}_{2} \overset{Δ}{⟶} \underset{5.0 g}{Pt}$

using POAC on Pt atom

mole of Pt in $B_{2} {(H_{2} {PtCCl}_{6}]}_{2}$ = mole of Pt atom in Product

$2 \times$ mole of $B_{2} {(H_{2} {PtCCl}_{6}]}_{2}$ = mole of Pt

$\frac{30 \times 2}{2 B + 410 \times 2} = \frac{5}{195}$

$\Rightarrow B = 760$

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