Q.

If 30% molecules have M = 20,000, 40% molecules have M = 30, 000, rest of them have M = 60, 000. The PDI =x×101 Then  x= 
 

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answer is 12.

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Detailed Solution

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M¯N=(30×20000)+(40×30000)+(30×60000)30+40+30             =36000M¯W=(30×200002)+(40×300002)+(30×600002)(30×20000)+(40×30000)+(30×60000)          =43333.33

Poly disparity index (PDI)   =M¯WM¯N

=43333.33336000=1.20=12×101x=12

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If 30% molecules have M = 20,000, 40% molecules have M = 30, 000, rest of them have M = 60, 000. The PDI =x×10−1 Then  x=