If  $\left[\begin{array}{ll}3& -2\\ 3& 0\\ 2& 4\end{array}\right]\left[\begin{array}{ll}y& y\\ x& x\end{array}\right]=\left[\begin{array}{ll}3& 3\\ 3y& 3y\\ 10& 10\end{array}\right]$, then the values of  $x\text{\hspace{0.17em}\hspace{0.17em}and\hspace{0.17em}\hspace{0.17em}}y$ is

$\left[\begin{array}{ll}3y-2x& 3y-2x\\ 3y& 3y\\ 2y+4x& 2y+4x\end{array}\right]=\left[\begin{array}{ll}3& 3\\ 3y& 3y\\ 10& 10\end{array}\right]$

Comparing elements we have

$3y-2x=3$

$2y+4x=10$

Solving (1) and (2), we get  $x=\frac{3}{2},y=2$