If $3f\left(x\right)-2f\left(\frac{1}{x}\right)=x$ then $f^1\left(2\right)=$

Put $x=\frac{1}{x}$

$3f\left(\frac{1}{x}\right)-2f\left(x\right)=\frac{1}{x}\_\_\_\_\_\_\_\_\_\left(2\right)$

Put $x=2$

$5f^1\left(2\right)=3-\frac{1}{2}$

$5f^1\left(2\right)=\frac{5}{2}$

$f^1\left(2\right)=\frac{1}{2}$