If 3iz3+12z2−18z+27i=0 , (where i=−1 ) then:

8iz3+12z2−18z+27i=0 (2iz+3)(4z2+9i)=02iz+3=0 and 4z2+9i=0⇒ z=−32i⇒ |z|=3/2 .

If 3iz3+12z2−18z+27i=0 , (where i=−1 ) then:

8iz3+12z2−18z+27i=0 (2iz+3)(4z2+9i)=02iz+3=0 and 4z2+9i=0⇒ z=−32i⇒ |z|=3/2 .

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If $3 i z^{3} + 12 z^{2} - 18 z + 27 i = 0$ , (where $i = \sqrt{- 1}$ ) then:

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$| z | = 3 / 2$

$| z | = 2 / 3$

$| z | = 1$

$| z | = 3 / 4$

answer is A.

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$8 i z^{3} + 12 z^{2} - 18 z + 27 i = 0$

$(2 i z + 3) (4 z^{2} + 9 i) = 0$

$2 i z + 3 = 0$ and $4 z^{2} + 9 i = 0$

$\Rightarrow$ $z = \frac{- 3}{2 i}$

$\Rightarrow$ $| z | = 3 / 2$ .

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If 3iz3+12z2−18z+27i=0 , (where i=−1 ) then:

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If $3 i z^{3} + 12 z^{2} - 18 z + 27 i = 0$ , (where $i = \sqrt{- 1}$ ) then: