If 3x2+x+1(x−1)4=Ax−1+B(x−1)2+C(x−1)3+D(x−1)4 then A + B - C + D =

Take x−1=y⇒3(y+1)2+y+1+1y4=3y2+7y3+5y4A + B - C + D = 0 + 3 - 7 + 5 = 1

If 3x2+x+1(x−1)4=Ax−1+B(x−1)2+C(x−1)3+D(x−1)4 then A + B - C + D =

Take x−1=y⇒3(y+1)2+y+1+1y4=3y2+7y3+5y4A + B - C + D = 0 + 3 - 7 + 5 = 1

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If $\frac{3 x^{2} + x + 1}{(x - 1)^{4}} = \frac{A}{x - 1} + \frac{B}{(x - 1)^{2}} + \frac{C}{(x - 1)^{3}} + \frac{D}{(x - 1)^{4}}$ then A + B - C + D =

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Take $x - 1 = y \Rightarrow \frac{3 (y + 1)^{2} + y + 1 + 1}{y^{4}}$
$= \frac{3}{y^{2}} + \frac{7}{y^{3}} + \frac{5}{y^{4}}$
A + B - C + D = 0 + 3 - 7 + 5 = 1

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If 3x2+x+1(x−1)4=Ax−1+B(x−1)2+C(x−1)3+D(x−1)4 then A + B - C + D =

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If $\frac{3 x^{2} + x + 1}{(x - 1)^{4}} = \frac{A}{x - 1} + \frac{B}{(x - 1)^{2}} + \frac{C}{(x - 1)^{3}} + \frac{D}{(x - 1)^{4}}$ then A + B - C + D =