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If $3 x^{5} - 7 x^{4} + 4 x^{3} + a x^{2} + b x + c = 0$ is a reciprocal equation of second type then(a, b, c) =

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(4, –7, 3)

(–4, 7, –3)

(–3, 7, –4)

(3, –7, 4)

answer is C.

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Detailed Solution

$p_{n} = - p_{n - 1}$

$c = - 3, b = 7, a = - 4$

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