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If 40 L of a gas is stored under a pressure of 150 atm at 300 K. How many moles of the gas are present in the cylinder?

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264 mol

244 mol

225 mol

2.5 mol

answer is B.

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Detailed Solution

According to ideal gas law,

$pV = nRT, p = 150 atm, V = 40 L, T = 300 K$

$n = \frac{pV}{RT} = \frac{150 \times 40}{0.082 \times 300} = 243.9 \approx 244 mol$

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