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If $(\begin{matrix} 4 9 \\ 3 0 \end{matrix}) = (\begin{matrix} x y^{2} \\ 3 0 \end{matrix})$ then (x, y) =

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(2, 3)

(2, ±3)

(4, ± 2)

(4, ± 3)

answer is D.

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Detailed Solution

$x = 4, y = \pm 3 \Rightarrow (x, y) = (4, \pm 3)$

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