If $$4sin(xy)$$−$$5cos(xy)=45$$, then $$dydx=$$

$$4cos(xy)$$[$$xdydx+y(1)$$]$$+5sin(xy)$$[x.$$dydx+y(1)$$]$$=0$$[$$xdydx+y$$][$$4cos(xy)+5sin(xy)$$]$$=0xdydx=$$−y⇒$$dydx=$$−yx

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If $4 \sin (x y) - 5 \cos (x y) = 4^{5}$ , then $\frac{d y}{d x} =$

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\frac{- x}{y}

\frac{- y}{x}

\frac{4 \sin (x y) - 5 \cos (x y)}{4 \cos (x y) + 5 \sin (x y)}

\frac{4 \cos (x y) + 5 \sin (x y)}{4 \sin (x y) - 5 \cos (x y)}

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detailed solution

Correct option is B

$4 \cos (x y) [x \frac{d y}{d x} + y (1)] + 5 \sin (x y) [x . \frac{d y}{d x} + y (1)] = 0$

$[x \frac{d y}{d x} + y] [4 \cos (x y) + 5 \sin (x y)] = 0$

$x \frac{d y}{d x} = - y \Rightarrow \frac{d y}{d x} = - \frac{y}{x}$

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If 4sin(xy)−5cos(xy)=45, then dydx=

Unlock the full solution & master the concept.

Ready to Test Your Skills?

free study material

If $4 \sin (x y) - 5 \cos (x y) = 4^{5}$ , then $\frac{d y}{d x} =$