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If  4sin(xy)5cos(xy)=45, then  dydx=

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a
xy
b
yx
c
4sin(xy)5cos(xy)4cos(xy)+5sin(xy)
d
4cos(xy)+5sin(xy)4sin(xy)5cos(xy)

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detailed solution

Correct option is B

4cos(xy)[xdydx+y(1)]+5sin(xy)[x.dydx+y(1)]=0

[xdydx+y][4cos(xy)+5sin(xy)]=0

xdydx=ydydx=yx

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