Q.

If (5, 12) and (24, 7) are the foci of a hyperbola passing though the origin then the eccentricity of the hyperbola is

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a

38612

b

386/13

c

38625

d

386/38

answer is A.

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Detailed Solution

Let S(5, 12) and S(24,7) be two foci and

P(0, 0) be a point on the conic

then  SP=25+144=169=13SP=(24)2+72=625=25SS=(245)2+(712)2=192+52=386

since the conic is a hyperbola, SPSP=2a, the length of transverse axis 

andSS=2ae,e  being the eccentricity.

 e=SSSPSP=38612

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