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If 5.85 g of $N a C l$ are dissolved in 90 g of water, the mole fraction of $N a C l$ is

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0.1

0.0196

0.3

0.2

answer is D.

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Detailed Solution

$x_{N a C l} = \frac{n_{N a C l}}{n_{N a C l} + n_{H_{2} O}}$

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