If 5 moles of BaCl₂ is mixed with 2 moles of Na₃PO₄, the maximum number of moles of Ba₃(PO₄)₂ formed is :

$\begin{array}{l}3{\mathrm{BaCl}}_2+2{\mathrm{Na}}_3{\mathrm{PO}}_4\to {\mathrm{Ba}}_3{\left({\mathrm{PO}}_4\right)}_2+6\mathrm{NaCl}\\ 3\text{ moles of }{\mathrm{BaCl}}_2\to 2\text{ moles of }{\mathrm{Na}}_3{\mathrm{PO}}_4\\ \mathrm{x}\to 2\text{ moles of }{\mathrm{Na}}_3{\mathrm{PO}}_4\\ \Rightarrow \mathrm{x}=3\text{ moles of }{\mathrm{BaCl}}_2\end{array}$
Limiting reagent is ${\mathrm{Na}}_3{\mathrm{PO}}_4$
2 moles of ${\mathrm{Na}}_3{\mathrm{PO}}_4\to$1 mole of ${\mathrm{Ba}}_3{\left({\mathrm{PO}}_4\right)}_2$
$\Rightarrow$1 mole of ${\mathrm{Ba}}_3{\left({\mathrm{PO}}_4\right)}_2$ will be formed