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Q.

If 50% of energy released during fission would be converted into electrical energy, then the number of fissions in a second in a nuclear reactor of 6.4MW output is (Energy per fission is 200MeV)

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a

$4 \times 10^{15}$

b

$4 \times 10^{18}$

c

$4 \times 10^{17}$

d

$4 \times 10^{16}$

answer is C.

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Detailed Solution

efficiency: $η = 50 % = 0.5$

Power output=6.4 MW

required No of fission per seconds: $n = \frac{power output}{efficiency \times energy per fission}$

$= \frac{6 .4 MW}{0.5 \times 200 MeV} = \frac{6 .4 \times 10^{6}}{0.5 \times 200 \times 10^{6} \times 1 .6 \times 10^{- 19}} = 4 \times 10^{17}$

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If 50% of energy released during fission would be converted into electrical energy, then the number of fissions in a second in a nuclear reactor of 6.4MW output is (Energy per fission is 200MeV)