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Q.

If 5cosx+12cosy=13 , then the maximum value of 5sinx+12siny  is k , then k=

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a

120

b

5!

c

120

d

230

answer is A, C.

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Detailed Solution

5cosx+12cosy=13(1)

Let 5sinx+12siny=A(2)

(1)2+(2)2169+120cos(xy)=169+A2

A2  is maximum, when cos(xy)  is maximum

But cos(xy)1

So, A2120(1)A120

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