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If $(- 6, - 4), (3, 5), (- 2, 1)$ are the vertices of a parallelogram, then the remaing vertex can be

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(0,-1)

(7,9)

(-1,0)

(-11,-8)

answer is C, D.

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Detailed Solution

$A = (- 6, - 4) B = (3, 5) C = (- 2, 1)$

$\underset{= (- 1, 0)}{D = A + B - C}, D \underset{= (- 11, - 8)}{= A - B + C}, D \underset{= (7, 10)}{= - A + B + C}$

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