AI Mentor

Check Your IQ

Free Expert Demo

Try Test

Courses

Dropper NEET Course Dropper JEE Course Class - 12 NEET Course Class - 12 JEE Course Class - 11 NEET Course Class - 11 JEE Course Class - 10 Foundation NEET Course Class - 10 Foundation JEE Course Class - 10 CBSE Course Class - 9 Foundation NEET Course Class - 9 Foundation JEE Course Class -9 CBSE Course Class - 8 CBSE Course Class - 7 CBSE Course Class - 6 CBSE Course

Offline Centres

Q.

If 6 pounds of the nuts that cost $1.20 per pound are mixed with 2 pounds of the nuts that cost $1.60 per pound, what is the cost per pound of the mixture?

see full answer

Your Exam Success, Personally Taken Care Of

1:1 expert mentors customize learning to your strength and weaknesses – so you score higher in school , IIT JEE and NEET entrance exams.

An Intiative by Sri Chaitanya

a

$1.30

b

$1.80

c

$1.40

d

$1.60

answer is A.

(Unlock A.I Detailed Solution for FREE)

Best Courses for You

JEE

JEE

NEET

NEET

Foundation JEE

Foundation JEE

Foundation NEET

Foundation NEET

CBSE

CBSE

Detailed Solution

Concept- By using the unitary method we will find the price of 1 pound of nuts, and also for 2 and 6 pounds of nuts. Then by adding both costs, we will have the total cost. Therefore, on dividing it with the total poundsthe of the mixture, we will have a cost of 1 pound of mixture.
For 6 pounds of nuts that cost $1.20 per pound,
1 pound of nuts

= $ 1.20

6 pounds of nuts becomes

6 \times 1.20 = $ 7.20

For 2 pounds of nuts that cost of $1.60 per pound,
1 pound of nuts

= $ 1.60

2 pounds of nuts becomes

2 \times 1.60 = $ 3.20

Total pounds of nuts

= 6 + 2 = 8 pounds

Therefore, the total cost 8 pounds mixture becomes

= $ 7.20 + $ 3.20 = $ 10.40

So, cost of 1 pound of mixture

= \frac{10.40}{8} = $ 1.30

Hence, the correct answer is option 1.

Watch 3-min video & get full concept clarity

courses

No courses found

Related Blogs

Get ₹ 1 crore* worth scholarship for JEE / NEET / Foundation

Result Producing online coaching for JEE/NEET of south India

Largest All India Test Series for JEE/NEET

Best Online Course for IIT JEE

Best Online Course for NEET

Best Online Course for CBSE

Ready to Test Your Skills?

Check your Performance Today with our Free Mock Test used by Toppers!

Take Free Test

Get Expert Academic Guidance – Connect with a Counselor Today!

Related Blogs

Get ₹ 1 crore* worth scholarship for JEE / NEET / Foundation

Result Producing online coaching for JEE/NEET of south India

Largest All India Test Series for JEE/NEET

Best Online Course for IIT JEE

Best Online Course for NEET

Best Online Course for CBSE

best study material, now at your finger tips!

live classes
progress tracking
24x7 mentored guidance
study plan analysis

download the app

gplay

mentor

Download the App

gplay

personalised 1:1 online tutoring