If a + b +c = 0, the straight line 2ax+3by+4c=0 passes through the fixed point

$$\begin{gathered} If a + b +c = 0 \Rightarrow c=-a-b \\ \Rightarrow put c=-a-b in the line 2ax+3by+4c=0 \\ \Rightarrow 2ax+3by+4(-a-b)=0 \\ \Rightarrow 2ax+3by-4a-4b=0 \\ \Rightarrow a(2x-4)+ b(3y-4)=0 \\ It is of the form a{L}_1+b{L}_2=0 \\ \Rightarrow 2x-4=0 , 3y-4=0 \\ \Rightarrow x=2 , y= \frac{4}{3} \end{gathered}$$