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If A is a 3×3 matrix and |Adj A|=16 then |A|=

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$\pm$ 4

–4

answer is C.

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Detailed Solution

$\begin{matrix} | A d j A | = 16 \\ |A d j A| = {|A|}^{n - 1} \\ {| A |}^{2} = 16 \Rightarrow | A | = 4 o r - 4 \end{matrix}$

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