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Q.

If A = tanθ, B = secθ, C = sinθ and D = cosθ, then the value of A2 B2 + 2CD is

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a

(C + D)2

b

− (C + D)2

c

(DC)2

d

− (CD)2

answer is D.

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Detailed Solution

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A2 B2 + 2CD = tan2θ − sec2θ + 2sinθcosθ

= −(sec2θ − tan2θ − 2sinθcosθ

= −(1 − 2 sinθcosθ)

= −(sin2θ + cos2θ − 2sinθcosθ

= −(sinθ − cosθ)

= − (CD)2

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