If a > 0 and Z=1+i2a−i has magnitude 25, then Z¯ =_____

Z=2ia+ia2+1,Now |Z|=25⇒ a=3⇒Z=3i−15⇒Z¯=−1−3i5

If a > 0 and Z=1+i2a−i has magnitude 25, then Z¯ =_____

Z=2ia+ia2+1,Now |Z|=25⇒ a=3⇒Z=3i−15⇒Z¯=−1−3i5

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If a > 0 and $Z = \frac{{(1 + i)}^{2}}{a - i}$ has magnitude $\sqrt{\frac{2}{5}}$ , then $\bar{Z}$ =_____

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$\frac{- 1}{5} - \frac{3 i}{5}$

$\frac{1}{5} - \frac{3 i}{5}$

$- \frac{1}{5} + \frac{3 i}{5}$

$\frac{- 3}{5} + \frac{3 i}{5}$

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$Z = \frac{2 i (a + i)}{a^{2} + 1},$ Now

$| Z | = \sqrt{\frac{2}{5}} \Rightarrow a = 3 \Rightarrow Z = \frac{3 i - 1}{5} \Rightarrow \bar{Z} = \frac{- 1 - 3 i}{5}$

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If a > 0 and Z=1+i2a−i has magnitude 25, then Z¯ =_____

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If a > 0 and $Z = \frac{{(1 + i)}^{2}}{a - i}$ has magnitude $\sqrt{\frac{2}{5}}$ , then $\bar{Z}$ =_____