If A=1−2−43, B=41−32 then 3A−2B=

Given,A=[1−2−43] B=[41−32] 3A=[3−6−129] 2B=[82−62] 3A−2B=[3−6−129]−[82−62] =[−5−8−65]

If A=1−2−43, B=41−32 then 3A−2B=

Given,A=[1−2−43] B=[41−32] 3A=[3−6−129] 2B=[82−62] 3A−2B=[3−6−129]−[82−62] =[−5−8−65]

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If $A = [\begin{matrix} 1 & - 2 \\ - 4 & 3 \end{matrix}], B = [\begin{matrix} 4 & 1 \\ - 3 & 2 \end{matrix}]$ then $3 A - 2 B =$

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$[\begin{matrix} - 5 & - 8 \\ 6 & - 5 \end{matrix}]$

$[\begin{matrix} 5 & - 8 \\ - 6 & 5 \end{matrix}]$

$[\begin{matrix} 5 & 8 \\ 6 & 5 \end{matrix}]$

$[\begin{matrix} - 5 & - 8 \\ - 6 & 5 \end{matrix}]$

answer is A.

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Detailed Solution

Given,

$A = [\begin{matrix} 1 & - 2 \\ - 4 & 3 \end{matrix}] B = [\begin{matrix} 4 & 1 \\ - 3 & 2 \end{matrix}] 3 A = [\begin{matrix} 3 & - 6 \\ - 12 & 9 \end{matrix}] 2 B = [\begin{matrix} 8 & 2 \\ - 6 & 2 \end{matrix}] 3 A - 2 B = [\begin{matrix} 3 & - 6 \\ - 12 & 9 \end{matrix}] - [\begin{matrix} 8 & 2 \\ - 6 & 2 \end{matrix}] = [\begin{matrix} - 5 & - 8 \\ - 6 & 5 \end{matrix}]$