If $A=(-2,3,4)$ and $B=(1,2,3)$ are two points and P is the point of intersection of AB and $zx$ - plane, then $P_x+P_y+P_z=$

$A(-2,3,4),B(1,2,3)$ are two points and P is the point of intersection of AB and xy-plane
$\Rightarrow AP:PB=-3:2$
$\Rightarrow P=\frac{-3B+2A}{-1}=3B-2A$
$P=3(1,2,3)-2(-2,3,4)=(7,0,1)$
$P_x+P_y+P_z=7+0+1=8$