If a→=2i^−3j^,b→=2j^+3k^ then (a→+b→).(a→−b→)=

a→+b→=2i^−j^+3k^a→−b→=2i^−5j^−3k^So, dot product=4+5−9=0

If a→=2i^−3j^,b→=2j^+3k^ then (a→+b→).(a→−b→)=

a→+b→=2i^−j^+3k^a→−b→=2i^−5j^−3k^So, dot product=4+5−9=0

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If $\vec{a} = 2 \hat{i} - 3 \hat{j}, \vec{b} = 2 \hat{j} + 3 \hat{k}$ then $(\vec{a} + \vec{b}) . (\vec{a} - \vec{b}) =$

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Detailed Solution

$\begin{array}{l} \vec{a} + \vec{b} = 2 \hat{i} - \hat{j} + 3 \hat{k} \\ \vec{a} - \vec{b} = 2 \hat{i} - 5 \hat{j} - 3 \hat{k} \end{array}$

So, dot product

$\begin{array}{l} = 4 + 5 - 9 \\ = 0 \end{array}$

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If a→=2i^−3j^,b→=2j^+3k^ then (a→+b→).(a→−b→)=

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If $\vec{a} = 2 \hat{i} - 3 \hat{j}, \vec{b} = 2 \hat{j} + 3 \hat{k}$ then $(\vec{a} + \vec{b}) . (\vec{a} - \vec{b}) =$