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Q.

If A and B are mutually exclusive such that P(A) = 0.4, P(A B) = 0.7 then P(B) =

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a

0.1

b

0.7

c

0.3

d

0.2

answer is A.

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Detailed Solution

P(AB)=P(A)+P(B)

0.7=0.4+P(B)

P(B)=0.3

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If A and B are mutually exclusive such that P(A) = 0.4, P(A∪ B) = 0.7 then P(B) =