If A and B are two events such that P(A) > 0 and P (B) ≠ 1 then P(A¯/B¯)=

P(A¯B¯)=P(A¯∩B¯)P(B)¯ = 1−P(A∪B)P(B¯)

If A and B are two events such that P(A) > 0 and P (B) ≠ 1 then P(A¯/B¯)=

P(A¯B¯)=P(A¯∩B¯)P(B)¯ = 1−P(A∪B)P(B¯)

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If A and B are two events such that P(A) > 0 and P (B) $\neq$ 1 then $P (\bar{A} / \bar{B}) =$

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$P (A \cap B)$

P(A $\cup$ B)

$\frac{1 - P (A \cup B)}{P (B)}$

$\frac{1 - P (A \cup B)}{P (\bar{B})}$

answer is C.

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Detailed Solution

$P (\frac{\bar{A}}{\bar{B}}) = \frac{P (\bar{A} \cap \bar{B})}{P (\bar{B)}}$

= $\frac{1 - P (A \cup B)}{P (\bar{B})}$

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If A and B are two events such that P(A) > 0 and P (B) ≠ 1 then P(A¯/B¯)=

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If A and B are two events such that P(A) > 0 and P (B) $\neq$ 1 then $P (\bar{A} / \bar{B}) =$