If A and B are mutually exclusive events with P(B)≠1, then PAB¯=

PA/(B¯)=PA−PA∩B1−PB=PA1−PB

PA/(B¯)=PA−PA∩B1−PB=PA1−PB

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If A and B are mutually exclusive events with $P (B) \neq 1$ , then $P (\frac{A}{\bar{B}}) =$

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$\frac{P (A)}{1 - P (B)}$

$\frac{1}{1 - P (B)}$

$\frac{P (A)}{P (B)}$

$\frac{1}{P (B)}$

answer is D.

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$P [A / (\bar{B})] = \frac{P (A) - P (A \cap B)}{1 - P (B)} = (\frac{P (A)}{1 - P (B)})$

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