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If $A$ and $B$ are two mutually exclusive events then

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$P (A) \leq P (\bar{B})$

$P (A) > P (\bar{B})$

$P (A) < P (B)$

$P (A) \leq P (B)$

answer is A.

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Detailed Solution

$A \cap B = ϕ$

We know that $P (A \cup B) \leq 1$

$\Rightarrow P (A) + P (B) \leq 1$

$\Rightarrow P (A) \leq 1 - P (B)$

$\Rightarrow P (A) \leq P (\bar{B})$

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