If A and B are two sets such that nA=16,nB=12 and A∩B=8 then nA∪B=

nA=16,nB=12 and nA∩B=8nA∪B=nA+nB-nA∩B=16+12-828-8=20

If A and B are two sets such that nA=16,nB=12 and A∩B=8 then nA∪B=

nA=16,nB=12 and nA∩B=8nA∪B=nA+nB-nA∩B=16+12-828-8=20

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If A and B are two sets such that $n (A) = 16, n (B) = 12$ and $(A \cap B) = 8 then n (A \cup B) =$

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Detailed Solution

$n (A) = 16, n (B) = 12$ and $n (A \cap B) = 8$

$n (A \cup B) = n (A) + n (B) - n (A \cap B)$

$= 16 + 12 - 8$

$28 - 8 = 20$

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If A and B are two sets such that nA=16,nB=12 and A∩B=8 then nA∪B=

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If A and B are two sets such that $n (A) = 16, n (B) = 12$ and $(A \cap B) = 8 then n (A \cup B) =$