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If $a \in ℤ$ and the equation $(x - a) (x - 10) + 1 = 0$ has integral roots, then the value of a are

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12,8

12,10

10,8

12,6

answer is B.

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Detailed Solution

$x - a = - 1 (o r) x - 10 = 1, x = a - 1, x = 11, a - 1 = 11, a = 12$

$x - a = 1, x - 10 = - 1, x = 1 + a, x = 9, 1 + a = 9 \Rightarrow a = 8$

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