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If a, b, and c are in H.P., then the value of  (ac+abbc)(ab+bcac)(abc)2 is 

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a
(a+c)(3ac)4a2c2
b
2bc1b2
c
2bc1a2
d
(ac)(3a+c)4a2c2

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detailed solution

Correct option is A

1b+1c1a1c+1a1b=1b+1c2b+1c1c+1b1c=2c1b1b=2bc1b2
Also by eliminating b, we get the given expression
(a+c)(3ac)4a2c2

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