If a¯,b¯ and c¯ are three vectors such that |a¯|=|b¯|=2, a¯.b¯=2 and a¯+b¯+c¯=0¯ then |c¯|=

|a¯|=|b¯|=2 a¯.b¯=2a¯+b¯=−c¯S.O.Bs(a¯+b¯)2=|c¯|2|a¯|2+|b¯|2+2a¯.b¯=|c¯|24+4+4=|c¯|2⇒|c¯|2=12⇒|c¯|=23

If a¯,b¯ and c¯ are three vectors such that |a¯|=|b¯|=2, a¯.b¯=2 and a¯+b¯+c¯=0¯ then |c¯|=

|a¯|=|b¯|=2 a¯.b¯=2a¯+b¯=−c¯S.O.Bs(a¯+b¯)2=|c¯|2|a¯|2+|b¯|2+2a¯.b¯=|c¯|24+4+4=|c¯|2⇒|c¯|2=12⇒|c¯|=23

AI Mentor

Check Your IQ

Free Expert Demo

Try Test

Courses

Dropper NEET Course Dropper JEE Course Class - 12 NEET Course Class - 12 JEE Course Class - 11 NEET Course Class - 11 JEE Course Class - 10 Foundation NEET Course Class - 10 Foundation JEE Course Class - 10 CBSE Course Class - 9 Foundation NEET Course Class - 9 Foundation JEE Course Class -9 CBSE Course Class - 8 CBSE Course Class - 7 CBSE Course Class - 6 CBSE Course

Offline Centres

If $\bar{a}, \bar{b} a n d \bar{c}$ are three vectors such that $| \bar{a} | = | \bar{b} | = 2, \bar{a} . \bar{b} = 2$ and $\bar{a} + \bar{b} + \bar{c} = \bar{0}$ then $| \bar{c} | =$

see full answer

Your Exam Success, Personally Taken Care Of

1:1 expert mentors customize learning to your strength and weaknesses – so you score higher in school , IIT JEE and NEET entrance exams.

An Intiative by Sri Chaitanya

$2 \sqrt{3}$

$\sqrt{3}$

answer is B.

(Unlock A.I Detailed Solution for FREE)

Best Courses for You

JEE

NEET

Foundation JEE

Foundation NEET

CBSE

Detailed Solution

$| \bar{a} | = | \bar{b} | = 2 \bar{a} . \bar{b} = 2$
$\bar{a} + \bar{b} = - \bar{c}$
S.O.Bs
${(\bar{a} + \bar{b})}^{2} = {| \bar{c} |}^{2}$
${| \bar{a} |}^{2} + {| \bar{b} |}^{2} + 2 \bar{a} . \bar{b} = {| \bar{c} |}^{2}$
$4 + 4 + 4 = {| \bar{c} |}^{2}$
$\Rightarrow {| \bar{c} |}^{2} = 12 \Rightarrow | \bar{c} | = 2 \sqrt{3}$