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Q.

If a,b:b,c:c,a are the roots of  x24x+3=0x28x+15=0 and  x26x+5=0 respectively. Compute  [a2+c2a2+b2b2+c2a2+c2]+[2ac2ab2bc2ac]

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a

[64416]

b

[364416]

c

[364416]

d

[164436]

answer is B.

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Detailed Solution

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 x24x+3=0x=1,3
 x28x+15=0x=3,5
 x26x+5=0x=5,1
 a=1,b=3,c=5
Now  [(a+c)2(ab)2(bc)2(ac)2]=[364416]

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