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Q.

If a,b,c are non zero real numbers and if the equations (a-1) x=y+z, (b-1)y=z+x,(c-1)z=x+y have a non-trival solution, then ab+bc+ca

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a

a2b2c2

b

a+b+c

c

0

d

abc

answer is B.

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Detailed Solution

Given system has non – trivial solution
⇒1−a1111−b1111−c=0⇒ab+bc+ca=abc

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