If  $a,b,c$  be three distinct natural numbers in Arithmetic Progression and  $a+b+c=2025,$ then the possible number of ordered pairs  $(a,b,c)$ is ___

$a+c=2b\Rightarrow 3b=2025\Rightarrow b=675\Rightarrow a+c=1350$

Number of positive integer solutions will be${ }^{1349}{C}_1=1349$ which includes  $675,675$  as the solution but shouldn’t be included