If A, B, C, D and E are five prime numbers, the sum of these five numbers = 266. It is given that

A< B< C< D< E then the value of is

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243

3125

Can’t determined

answer is B.

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Detailed Solution

We are given in question that there are total 5 prime numbers A, B, C, D and E and their sum is 266
With condition A<B<C<D<E
and we have to find

.

Given A+B+C+D+E=266
Now considering 2 conditions
1. All the prime numbers are odd except 2
2.If we have odd numbers in even quantity then their sum will be even and if they are present in odd quantity then their sum will be odd
Assume that A, B, C, D and E all are odd numbers,
But their quantity is 5
And we know that all odd numbers present in odd quantity then their sum will be odd but we got our sum as even it means out of 5 numbers there is 1 even and 4 odd number, only even prime number is 2
And we have this condition A<B<C<D<E and we know that 2 is the smallest prime number so it means value of A is 2
Now it's very easy we just have to find

= 32

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