If a block of iron(density 5 g cm-3) is size 5 cm ×5 cm ×5 cm was weighed while completely submerged in water, what would be the apparent weight?

Upthrust = 5×5×5×1 gWeight = 5×5×5×5 gApparent weight = 5 ×5×5(5-1)g = 5×5×5×4 g

If a block of iron(density 5 g cm-3) is size 5 cm ×5 cm ×5 cm was weighed while completely submerged in water, what would be the apparent weight?

Upthrust = 5×5×5×1 gWeight = 5×5×5×5 gApparent weight = 5 ×5×5(5-1)g = 5×5×5×4 g

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If a block of iron(density 5 g ${cm}^{- 3}$ ) is size 5 cm $\times$ 5 cm $\times$ 5 cm was weighed while completely submerged in water, what would be the apparent weight?

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$5 \times 5 \times 5 \times 5 g$

$4 \times 4 \times 4 \times 5 g$

$3 \times 5 \times 5 \times 5 g$

$4 \times 5 \times 5 \times 5 g$

answer is D.

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Detailed Solution

Upthrust = $5 \times 5 \times 5 \times 1 g$

Weight = $5 \times 5 \times 5 \times 5 g$

Apparent weight = $5 \times 5 \times 5 (5 - 1) g$

= $5 \times 5 \times 5 \times 4 g$

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If a block of iron(density 5 g cm-3) is size 5 cm ×5 cm ×5 cm was weighed while completely submerged in water, what would be the apparent weight?

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If a block of iron(density 5 g ${cm}^{- 3}$ ) is size 5 cm $\times$ 5 cm $\times$ 5 cm was weighed while completely submerged in water, what would be the apparent weight?