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Q.

If a body of mass 36gm moves with S.H.M of amplitude A = 13cm and period T = 12 Sec. At a time t = 0, the displacement, x is +13cm, the magnitude force acting on the body in dynes. When t = 2 sec.( take $π^{2} = 10$ )

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answer is 65.

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Detailed Solution

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$X = Acos ωt$ (since the particle is moving from the extreme position towards the equilibrium position)

$x = Acos \frac{2 π}{12} \times 2 = Acos \frac{π}{3} = \frac{A}{2} = 6 .5 cm (∵ A = 13 cm)$

$F = Force acting on the body = - {mω}^{2} x = - 36 \times \frac{4 π^{2}}{12 \times 12} \times 6 .5 = - 65 dyne.$

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If a body of mass 36gm moves with S.H.M of amplitude A = 13cm and period T = 12 Sec. At a time t = 0, the displacement, x is +13cm, the magnitude force acting on the body in dynes. When t = 2 sec.( take π2=10)