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Q.

If a body starts from rest and travels 120 cm in the 6th second then what is the acceleration?

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a

$0.318 m / s^{2}$

b

$0.518 m / s^{2}$

c

$0.218 m / s^{2}$

d

$0.418 m / s^{2}$

answer is A.

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Detailed Solution

$S_{n} = u + \frac{a}{2} (2 n - 1)$

$\frac{120}{100} = \frac{a}{2} (2 \times 6 - 1)$

$a = \frac{24}{10 \times 11} = 0.218 {ms}^{- 2}$

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