If a bromine atom is available in the form of, say, two isotopes 35Br79 (49.7%) and 35Br81 (50.3%), calculate the average atomic mass of the bromine atom.

The average atomic mass of Br = [(Atomic mass of 35Br79 × percentage) + (Atomic mass of 35Br81 × percentage)]/100=[79×49.7 + 81×50.3]/100=80.006 u

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If a bromine atom is available in the form of, say, two isotopes ₃₅Br⁷⁹ (49.7%) and ₃₅Br⁸¹ (50.3%), calculate the average atomic mass of the bromine atom.

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answer is 80.006.

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The average atomic mass of Br = [(Atomic mass of ₃₅Br⁷⁹× percentage) + (Atomic mass of ₃₅Br⁸¹ × percentage)]/100

=[79×49.7 + 81×50.3]/100

=80.006 u

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