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If a bullet of mass 5 gm moving with velocity 100 m /sec, penetrates the wooden block upto 6 cm. Then the average force imposed by the bullet on the block is

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8300 N

417 N

830 N

Zero

answer is B.

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Detailed Solution

$u = 100 m / s, v = 0, s = 0 .06 m Retardation = a = \frac{u^{2}}{2 s} = \frac{(100)^{2}}{2 \times 0 .06} = \frac{1 \times 10^{6}}{12} ∴ Force = ma = \frac{5 \times 10^{- 3} \times 1 \times 10^{6}}{12} = \frac{5000}{12} = 417 N$

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